已解决输入出生年月日，和今天的年月日，然后求出出生到今天的总天数(上次没记录)

#include "stdio.h"
#include "conio.h"

main()
{
int year1,month1,date1;
int year2,month2,date2;
int i,days=0,day1,day2;
int maxmonth;
int d[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
scanf("%d%d%d\n%d%d%d",&year1,&month1,&date1,&year2,&month2,&date2);
for(i=year1;i<year2;i++)
{
if(i%4==0||i%400==0)
{
days+=366;
}
else
{
days+=365;
}
}
if(month1>month2)
{
maxmonth = month1;
month1 = month2;
month2 = maxmonth;
}
for(i=month1;i<month2;i++)
{

days=days+d;
}
days=days+date2-date1;
if(year2%4==0||year2%400==0&&month2>2)days++;
printf("the days is %d",days);
getch();
}


这是上次版主提示后我自己回忆做的，但是这样肯定是有问题的， 版主请纠正一下吧？？

// 很久没来关注程序版了。。。
#include <iostream>
using namespace std;

class date
{
public:
int year;
int month;
int day;
public:
date(int y=1,int m=1,int d=1):year(y),month(m),day(d){}
bool isleapyear ();
int getyeardays ();
int getmonthdays ();
int datetonum();
};

ostream &operator<<(ostream &out,const date &d);
istream &operator>>(istream &in,date &d);


bool date::isleapyear()
{
if(year%4==0 && year%100 !=0 || year%400==0) return true;
else return false;
}

int date::getyeardays()
{
if (isleapyear()) return 366;
else return 365;
}

int date::getmonthdays()
{
int n;
switch (month)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
牋 n=31;
牋牋牋break;
case 4:
case 6:
case 9:
case 11:
牋牋 n=30;
牋牋 break;
牋 case 2:
牋 if(isleapyear()) n=29;
牋 else n=28;
}
return n;
}

int date::datetonum()
{
int n=0;
int tempyear=year;
int tempmonth=month;
for (month=1;month<tempmonth;month++)
n+=getmonthdays();
for (year=1;year<tempyear;year++)
n+=getyeardays();
n+=day;
return n;
}


ostream &operator<<(ostream &out,const date &d)
{
out<<d.year<<"-"<<d.month<<"-"<<d.day<<endl;
return out;
}

istream &operator>>(istream &in,date&d)
{
int year,month,day;
cout<<" 请输入年份: ";
cin>>year;
cout<<" 请输入月份: ";
cin>>month;
cout<<" 请输入日期: ";
cin>>day;
d=date(year,month,day);
return in;
}


void main()
{
date d1;
date d2;
int result=0;
cout<<"请输入你的生日:"<<endl;
cin>>d1;
cout<<"请输入当前日期:"<<endl;
cin>>d2;
cout<<d1<<d2;

result=d1.datetonum()-d2.datetonum();
if(result<0)
牋 result=-1*result;
cout<<"总天数相差 "<<result<<" 天。"<<endl;
}